fix formatting in docs (#755)

Author: JoshuaLampert

docs/src/user/limitations.md

@@ -7,10 +7,7 @@ function being differentiated):
 
 - **The target function can only be composed of generic Julia functions.** ForwardDiff cannot propagate derivative information through non-Julia code. Thus, your function may not work if it makes calls to external, non-Julia programs, e.g. uses explicit BLAS calls instead of `Ax_mul_Bx`-style functions.
 
-- **The target function must be a composition of differentiable functions.** ForwardDiff can have issues to compute derivatives of functions, which are composed of at least one function, which is not differentiable in the point the derivative should be
-evaluated, even if the target function itself is differentiable. A simple example is `f(x) = norm(x)^2`, where `ForwardDiff.gradient(f, zeros(2))` returns a vector of `NaN`s since the Euclidean norm is not differentiable in zero. A possible solution to
-this issue is to, e.g., define `f(x) = sum(abs2, x)` instead. In situations, where rewriting the target function only as a composition of differentiable functions is more complicated (e.g. `f(x) = (1 + norm(x))exp(-norm(x))`)), one would need to define
-a custom derivative rule (see [this comment](https://github.com/JuliaDiff/ForwardDiff.jl/issues/303#issuecomment-2977990425)).
+- **The target function must be a composition of differentiable functions.** ForwardDiff can have issues to compute derivatives of functions, which are composed of at least one function, which is not differentiable in the point the derivative should be evaluated, even if the target function itself is differentiable. A simple example is `f(x) = norm(x)^2`, where `ForwardDiff.gradient(f, zeros(2))` returns a vector of `NaN`s since the Euclidean norm is not differentiable in zero. A possible solution to this issue is to, e.g., define `f(x) = sum(abs2, x)` instead. In situations, where rewriting the target function only as a composition of differentiable functions is more complicated (e.g. `f(x) = (1 + norm(x))exp(-norm(x))`)), one would need to define a custom derivative rule (see [this comment](https://github.com/JuliaDiff/ForwardDiff.jl/issues/303#issuecomment-2977990425)).
 
 - **The target function must be unary (i.e., only accept a single argument).** [`ForwardDiff.jacobian`](@ref) is an exception to this rule.