165. Compare Version Numbers

[mah-shamim]

Topics: Two Pointers, String

Given two version numbers, version1 and version2, compare them.

Version numbers consist of one or more revisions joined by a dot '.'. Each revision consists of digits and may contain leading zeros. Every revision contains at least one character. Revisions are 0-indexed from left to right, with the leftmost revision being revision 0, the next revision being revision 1, and so on. For example 2.5.33 and 0.1 are valid version numbers.

To compare version numbers, compare their revisions in left-to-right order. Revisions are compared using their integer value ignoring any leading zeros. This means that revisions 1 and 001 are considered equal. If a version number does not specify a revision at an index, then treat the revision as 0. For example, version 1.0 is less than version 1.1 because their revision 0s are the same, but their revision 1s are 0 and 1 respectively, and 0 < 1.

Return the following:

• If version1 < version2, return -1.
• If version1 > version2, return 1.
• Otherwise, return 0.

Example 1:

• Input: version1 = "1.01", version2 = "1.001"
• Output: 0
• Explanation: Ignoring leading zeroes, both "01" and "001" represent the same integer "1".

Example 2:

• Input: version1 = "1.0", version2 = "1.0.0"
• Output: 0
• Explanation: version1 does not specify revision 2, which means it is treated as "0".

Example 3:

• Input: version1 = "0.1", version2 = "1.1"
• Output: -1
• Explanation: version1's revision 0 is "0", while version2's revision 0 is "1". 0 < 1, so version1 < version2.

Constraints:

• 1 <= version1.length, version2.length <= 500
• version1 and version2 only contain digits and '.'.
• version1 and version2 are valid version numbers.
• All the given revisions in version1 and version2 can be stored in a 32-bit integer.

Hint:

1. You can use two pointers for each version string to traverse them together while comparing the corresponding segments.
2. Utilize the substring method to extract each version segment delimited by '.'. Ensure you're extracting the segments correctly by adjusting the start and end indices accordingly.

[topugit]

We can use a two-pointer approach to traverse each version number and compare their segments.

1. Split the Versions: Use explode to split each version number by the dot '.' character into arrays of segments.
2. Traverse and Compare Segments: Use two pointers to traverse the segments of each version. Compare corresponding segments as integers, taking care of leading zeros and treating missing segments as 0.

Let's implement this solution in PHP: 165. Compare Version Numbers

<?php
function compareVersion($version1, $version2) {
    // Split the version numbers into arrays of segments
    $v1 = explode('.', $version1);
    $v2 = explode('.', $version2);
    
    // Get the maximum length to iterate over both arrays
    $length = max(count($v1), count($v2));
    
    // Compare each segment
    for ($i = 0; $i < $length; $i++) {
        // Get the current segment from each version, defaulting to "0" if not present
        $seg1 = isset($v1[$i]) ? (int)$v1[$i] : 0;
        $seg2 = isset($v2[$i]) ? (int)$v2[$i] : 0;
        
        // Compare segments
        if ($seg1 < $seg2) {
            return -1;
        } elseif ($seg1 > $seg2) {
            return 1;
        }
    }
    
    // All segments are equal
    return 0;
}

// Example usage
echo compareVersion("1.01", "1.001"); // Output: 0
echo compareVersion("1.0", "1.0.0"); // Output: 0
echo compareVersion("0.1", "1.1"); // Output: -1
?>

Explanation:

1. Splitting Versions:

   • explode('.', $version1) and explode('.', $version2) convert each version string into arrays of segments based on the dot delimiter.

2. Traversing Segments:

   • max(count($v1), count($v2)) ensures that the loop runs through the longest of the two version arrays.
   • isset($v1[$i]) ? (int)$v1[$i] : 0 gets the segment value or defaults to 0 if the segment does not exist.

3. Comparing Segments:

   • Compare each segment as integers to handle leading zeros.
   • Return -1 if the first version is less, 1 if it is greater, and 0 if they are equal after all segments are compared.

This solution efficiently compares version numbers by considering each segment as an integer and handles cases where versions have different lengths by treating missing segments as 0.

[mah-shamim]

Thanks to solve the problem of comparing two version numbers