Clarification for 0.5 value in the formula of Regression model #60
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…n the classification notebook.
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in file: /Jupyter_Notebooks/Chapter_01_Supervised_Learning/02-Linear_Classification/02-Linear_Classification.ipynb
section 2, regarding this line:
decision_boundary = (-w1 * x_vals - w0 + 0.5) / w2
extra explanation added to clarify 0.5 in the formula