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The student's solution demonstrates a good understanding of binary search algorithms and applies them effectively to solve the given problems. Here's a detailed evaluation:

  1. Correctness:

    • Problem 1 (Find First and Last Position): The solution correctly implements binary search twice to find the first and last occurrences of the target. It handles the case when the target is not found appropriately.
    • Problem 2 (Find Minimum in Rotated Sorted Array): The solution correctly identifies the pivot point where the minimum element resides. It handles the rotation logic well.
    • Problem 3 (Find Peak Element): The solution correctly implements binary search to find a peak element, considering the given constraints.
  2. Time Complexity:

    • All solutions maintain O(log n) time complexity, which meets the problem requirements.
  3. Space Complexity:

    • All solutions use O(1) additional space, which is optimal.
  4. Code Quality:

    • The code is well-structured and readable.
    • For Problem 1, the use of a helper function (findBound) is a good practice to avoid code duplication.
    • Variable names are clear and appropriate.
    • The solutions could benefit from brief comments explaining the logic, especially for Problem 2 and 3 where the binary search conditions might not be immediately obvious.
  5. Efficiency:

    • The solutions are already efficient, but for Problem 2, the condition else: right -= 1 is unnecessary since the problem states there are no duplicates. This line could be removed.

Potential Edge Cases:

  • For Problem 1, the solution handles empty arrays implicitly (since len(nums)-1 would be -1 and the loop won't execute), but it might be worth explicitly mentioning this case.
  • For Problem 3, the solution works for arrays of length 1, but this edge case could be explicitly checked for clarity.

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